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- Newsgroups: sci.math
- Path: sparky!uunet!newsgate.watson.ibm.com!yktnews!admin!yktnews!victor
- From: victor@watson.ibm.com (Victor Miller)
- Subject: Re: Extended Fermat primes
- Sender: news@watson.ibm.com (NNTP News Poster)
- Message-ID: <VICTOR.92Nov12094523@terse.watson.ibm.com>
- In-Reply-To: kasdan@cs.columbia.edu's message of Wed, 11 Nov 1992 21:21:13 GMT
- Date: Thu, 12 Nov 1992 14:45:23 GMT
- Reply-To: victor@watson.ibm.com
- Disclaimer: This posting represents the poster's views, not necessarily those of IBM
- References: <1992Nov7.172207.17207@husc15.harvard.edu>
- <1992Nov8.004737.13519@Princeton.EDU> <BxKLzE.Bu9@cs.columbia.edu>
- Nntp-Posting-Host: terse.watson.ibm.com
- Organization: IBM, T.J. Watson Research Center
- Lines: 43
-
- >>>>> On Wed, 11 Nov 1992 21:21:13 GMT, kasdan@cs.columbia.edu (John Kasdan) said:
-
- John> In article <1992Nov8.004737.13519@Princeton.EDU> tao@fine.princeton.edu (Terry Tao) writes:
- Terry>
- Terry> .... And it is highly likely that there are infinitely many primes
- Terry> of the form n^4 + 1, n^8 + 1, etc. on the grounds that any polynomial which
- Terry> is not factorizable should give infinitely many primes. (Is there a name
- Terry> for this conjecture? if you know it could you email me?)
- Terry>
-
- John> I doubt that there is a name for the conjecture in that form, because
- John> it is obviously false. Consider x^2 + x + 2.
-
- John, There is actually a conjecture like this. I don't remember what
- it is called in general. Obviously, it needs to be stated in a
- modified form: the polynomial x^2+x+2 is always divisible by 2 at
- integer values, so consider (1/2)(x^2+x+2). The generalization is as
- follows:
-
- Let (x;n) = x(x-1)...(x-n+1)/n!. Then show that a polynomial with
- rational coefficients takes on integer values at integer values of
- it's argument if and only if it is an integral linear combination of
- the (x;n). In your case, your polynomial was: 2 (x;2) + 2(x;1) +
- 2(x;0).
-
- A more usual conjecture has to do with generalizing arithmetic
- progressions:
- If f(x) is an irreducible polynomial over Q, with no fixed divisor
- (i.e. the gcd of the coefficients in the expansion into (x;j) is 1),
- then there are infinitely many primes of the form f(x).
-
- Unfortunately, this is unknown for any polynomial above first degree!
-
- Terry> Terry
-
- John> /JK
-
- --
- Victor S. Miller
- Bitnet: VICTOR at WATSON
- Internet: victor@watson.ibm.com
- IBM, TJ Watson Research Center
- "Great artists steal; lesser artists borrow" Igor Stravinsky
-