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- Newsgroups: sci.math
- Path: sparky!uunet!news.uiowa.edu!news
- From: daf@herky.cs.uiowa.edu (David Forsyth)
- Subject: Re: Collineations
- Sender: news@news.uiowa.edu (News)
- Message-ID: <1992Aug12.205843.15633@news.uiowa.edu>
- Date: Wed, 12 Aug 1992 20:58:43 GMT
- References: <1992Aug12.194204.24356@uwm.edu>
- Nntp-Posting-Host: herky.cs.uiowa.edu
- Organization: University of Iowa, Iowa City, IA, USA
- Lines: 28
-
- From article <1992Aug12.194204.24356@uwm.edu>, by radcliff@csd4.csd.uwm.edu (David G Radcliffe):
- > Suppose f is a one-to-one function from the plane to itself
- > which maps lines into lines, and suppose the image of f is
- > not contained in a line. Must f be affine?
- >
- > I have found some partial results. The restriction of f to
- > Q^2 is equal to the restriction of a projective transformation.
- > If one also assumes that f is surjective, or continuous, or that
- > it preserves betweenness, then f must be affine.
- >
- > --
- > David Radcliffe
- > radcliff@csd4.csd.uwm.edu
- If memory serves me correctly, for the projective plane, the requirement
- that f be a collineation and one-to-one guarantees that f is a projective
- transformation. This would mean that for the affine case, f would be a projective
- transformation that kept the line at infinity at infinity, hence an affine
- transformation. I think the first fact (result?) is in Semple and Kneebone,
- Algebraic Projective Geometry, Oxford University press, but they probably didn't
- prove it all that rigorously.
-
- Regards
-
- David Forsyth
- .
-
- :wq
-
-