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- Xref: sparky rec.music.cd:8555 rec.audio:17129
- Path: sparky!uunet!think.com!spool.mu.edu!darwin.sura.net!dtix!oasys!curt
- From: curt@oasys.dt.navy.mil (Curt Welch)
- Newsgroups: rec.music.cd,rec.audio
- Subject: Re: MiniDiscs -- What Are They?
- Message-ID: <28844@oasys.dt.navy.mil>
- Date: 22 Dec 92 05:19:45 GMT
- References: <BzB4Lz.LLL@newcastle.ac.uk> <1992Dec22.013311.22956@dgbt.doc.ca>
- Reply-To: curt@oasys.dt.navy.mil (Curt Welch)
- Followup-To: rec.music.cd
- Organization: Carderock Division, NSWC, Bethesda, MD
- Lines: 48
-
- > rhoades@ll.mit.edu (Captain Chaos) writes:
- >I toss out 150 MB as a guess at MD
- >capacity (CD-ROM=600+ MB, MD has ~1/4 the data a CD has).
-
- In rec.audio, ted@dgbt.doc.ca (Ted Grusec) writes:
- >MD, and DCC both use lossy compression. Therefore, they are TOTALLY
- >USELESS for computer storage!
-
- Ted. You are confused. Think about it. If you still think it won't
- work, get someone to explain it to you.
-
- On the size of the MD, I worked out the likely size last night using
- numbers from an article in MIX. It came out to about 135 MB - but
- I had to make some assumptions about how the MD would be used
- for data storage.
-
- The numbers from the article: The MD ATRAC encoding takes 512 stereo 16
- bit samples (2048 bytes) and compresses them into a 424 byte sound
- group (212 bytes for each channel). This gives the fixed compression
- ratio of about 4.83 to 1.
-
- 11 of these sound groups get packed into every 2 sectors. A sector
- contains 2332 bytes of data plus 20 bytes of other data. I assume
- this other data is for error correction but the article isn't clear.
-
- 32 of these sectors are grouped into a cluster. The cluster has 36
- sectors total. 32 for data, 3 for link data (used to form the linked
- list I assume) and one for subcode data.
-
- The 512 samples that are compressed into a sound group make up about
- 11.6 msec of music. A sector (5.5 groups) holds 63.9 msec of music.
- A cluster, (32 sectors) holds 2.04 seconds of music.
-
- If a disk can hold 74 minutes of music, that would be about 2173
- clusters on a disk.
-
- For data, I assume they would store one 2048 block in each 2332 byte
- sector. This is similar to how CD-ROMS work where they store 2048
- bytes in each 2352 byte subcode block.
-
- Doing this would yeld 2173 (clusters) * 32 (sectors per cluster) *
- 2048 (bytes per sector) or 142409728 bytes. If you call 1024^2 a MB,
- then this would be 135.8 MB.
-
- I sure hope they come out with a MD data drive RSN. 135 MB on
- a 2 1/2" disk for $12. Sounds good to me.
-
- Curt Welch
-