home *** CD-ROM | disk | FTP | other *** search
- Xref: sparky rec.boats:8847 sci.physics:21988
- Path: sparky!uunet!portal!cup.portal.com!dbell
- From: dbell@cup.portal.com (David J Bell)
- Newsgroups: rec.boats,sci.physics
- Subject: Re: inverter electric lesson
- Message-ID: <72725@cup.portal.com>
- Date: Thu, 31 Dec 92 23:14:39 PST
- Organization: The Portal System (TM)
- Distribution: na
- References: <mshulman.20.725843864@genghis.borland.com>
- <1i06daINNjvq@calvin.NYU.EDU>
- Lines: 28
-
- Roy Smith <roy@nyu.edu> wrote:
-
- >mshulman@genghis.borland.com (Michael Shulman) writes:
- .
- .
- .
- >>
- >>So, the 600W microwave takes about 60A per hour of operation at 12V,
- >>depending on the efficiency of the inverter.
-
- > Sigh. I guess I went a bit overboard with my "doctor dissertation
- >in electrical engineering", but obviously it didn't sink in. I'll try and
- >be more succinct this time.
-
- > 2) It is totally meaningless to say something takes "60A per hour".
- >Amps is a unit of current. I havn't the foggiest idea what "amps per hour"
- >is a unit of. I am reasonably certain, but not absolutely sure, that what
- >you meant to say is "the 600W microwave draws about 60A at 12V, which means
- >it eats up 60AH of charge per hour of operaton". It's more than just a
- >matter of semantics (or even pedantics).
-
- Well, perhaps not *totally* meaningless, albeit more or less useless:
- I would look at "Amps/Hour" dimensionally as a rate of change of current.
- As I said, not particularly useful, and almost certainly not what was
- meant in the original posting!
-
- Dave
- dbell@cup.portal.com
-