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  1. Newsgroups: sci.math
  2. Path: sparky!uunet!zaphod.mps.ohio-state.edu!cs.utexas.edu!qt.cs.utexas.edu!yale.edu!spool.mu.edu!agate!stanford.edu!Csli!hiraga
  3. From: hiraga@Csli.Stanford.EDU (Yuzuru Hiraga)
  4. Subject: Re: need proof:  (1 + 1/n)^n ==> e
  5. Message-ID: <1992Dec18.011331.12250@Csli.Stanford.EDU>
  6. Organization: Stanford University CSLI
  7. References: <1glr2qINN2vg@usenet.INS.CWRU.Edu> <1glt0lINNquc@news.aero.org> <1992Dec18.010543.11995@Csli.Stanford.EDU>
  8. Date: Fri, 18 Dec 1992 01:13:31 GMT
  9. Lines: 7
  10.  
  11. In article <1992Dec18.010543.11995@Csli.Stanford.EDU> hiraga@Csli.Stanford.EDU (Yuzuru Hiraga) writes:
  12. >Given e = (1 + 1/n)^n, prove that (e^x)' = e^x;
  13. >which boils down to lim(h->0) (e^h - 1)/h = 1.
  14.  
  15. Sorry, the first eq. is obviously e = lim(n->oo) (1+1/n)^n.
  16.  
  17. -YH
  18.