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- From: dmc@sjfc.UUCP (Cass Dan)
- Newsgroups: sci.math
- Subject: Forcing f(x) to have horizontal asymptote at +infinity
- Keywords: none
- Message-ID: <2317@sjfc.UUCP>
- Date: 16 Dec 92 00:14:25 GMT
- Organization: St. John Fisher College, Rochester, NY
- Lines: 33
-
- The function f(x) = ln(x) has its derivative 1/x approaching
- zero as x --> +infinity, yet f(x) itself has no horizontal
- asymptote. Even though the curve gets arbitrarily flat, nonetheless
- it never levels out.
-
- For comparison, the function f(x) = arctan(x) has its derivative
- 1/(1 + x^2) approaching zero as x --> +infinity, but this time
- f(x) *does* have an asymptote, namely y=pi/2.
-
- My question is: what conditions must be imposed on the derivative
- f'(x) of a function f(x) in order to cause it to necessarily have
- a horizontal asymptote as x --> +infinity ?
-
- Maybe a condition on both f'(x) and f''(x), since the latter is
- related to curvature....
-
- More formally, can the existence/nonexistence of a horizontal asymptote
- for the function f(x) as x --> +infinity be decided in terms of
- a) the values of lim [x --> +infinity] f'(x), f''(x), etc ?
- b) the asymptotic behavior of these derivatives f', f'',
- etc as x --> +infinity ?
-
- This question could be thought of as an "at infinity" version of
- the fact that, IF f' = 0 for all x, THEN f = constant [true if
- f is a smooth function]. What I'm asking is: if we want to conclude
- that f(x) --> constant as x --> +infinity, what limiting type
- conditions must we place on the derivatives of f?
-
- Respond here or to dmc@sjfc.edu
- --Dan Cass
-
- /-++#: /-==+ not much of a sig
-
-