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- Newsgroups: sci.math
- Path: sparky!uunet!comp.vuw.ac.nz!cc-server4.massey.ac.nz!TMoore@massey.ac.nz
- From: news@massey.ac.nz (USENET News System)
- Subject: Re: '-' operation
- Message-ID: <1992Dec16.031820.29270@massey.ac.nz>
- Organization: Massey University
- References: <92350.145501B7D@psuvm.psu.edu>
- Date: Wed, 16 Dec 92 03:18:20 GMT
- Lines: 24
-
- In article <92350.145501B7D@psuvm.psu.edu>, <B7D@psuvm.psu.edu> writes:
- >
- > Recently my daughter brought back Problem Set II of Wisconsin Mathematics
- > Science and Engineering Talent Search, and Question 4 in it is as following:
- > Operation @ satisfies the conditions that
- > X @ (Y @ Z) = X @ Y + Z and X @ X = 0 for any real numbers
- > X, Y, Z. Show that @ must be subtraction.
-
- An assumption is made here, but not stated, that @ has higher priority than +.
-
- As you showed, x@0 = x@(x@x) = x@x + x = 0 + x = x.
-
- Now you need to show that x@y = z <=> x = z + y.
-
- Now, x = x@0 = x@(y@y) = x@y + y
- and if x = z + y then z = x@y and conversely.
-
- Conversely, if y = x@z then x = y + z
-
- Note that, you _do_ need a clear idea what you wish to prove -
- in this case, because subtraction is usually defined as the
- inverse of addition you need to prove the equivalence above.
-
- Terry Moore
-