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- From: doudd@sofya.math.byu.edu (Darrin Doud)
- Newsgroups: sci.math
- Subject: Re: '-' operation
- Date: 15 Dec 1992 22:40:15 GMT
- Organization: Brigham Young University
- Lines: 23
- Distribution: world
- Message-ID: <1glmsfINN5sc@hamblin.math.byu.edu>
- References: <92350.145501B7D@psuvm.psu.edu>
- Reply-To: doudd@sofya.math.byu.edu (Darrin Doud)
- NNTP-Posting-Host: sofya.math.byu.edu
-
- >Recently my daughter brought back Problem Set II of Wisconsin Mathematics
- >Science and Engineering Talent Search, and Question 4 in it is as following:
- > Operation @ satisfies the conditions that
- > X @ (Y @ Z) = X @ Y + Z and X @ X = 0 for any real numbers
- > X, Y, Z. Show that @ must be subtraction.
- > Since my daughter does not care much whether she has talent so I tried to
- > solve it myself:-). It took me more than an hour but still I am not sure I get
- > a right answer. The problem I have is: How is operation '-' defined? How about
- > other operations like '+', '*', and '/'? Although I do not have Ph.D
- > in math but I consider myself one of the best in learning math in those
- > math classes. It is sort of ashameful that I never learned or remember
- > how the basic operation is defined. For the above question, is only
- > thing I have to prove is X @ 0 = X?, which is not very difficult because
- > X @ 0 = X @ (X @ X) = X @ X + X = 0 + X = X.
-
-
- Subtraction is defined to be the inverse operation of addition. We do need to
- prove more than that X@0=X, although that is a helpful first step. What we do
- need to do is show that X@Y=X-Y for any pair of numbers X and Y. We can
- do this as follows:
-
- X@Y = (X@Y+Y)-Y = X (Y@Y)-Y = X@0 -Y = X-Y
-
-