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- From: li@sce.carleton.ca (Yao Li)
- Newsgroups: sci.math
- Subject: answer to "math problem"
- Message-ID: <9212140156.AA18233@mariner.sce.carleton.ca>
- Date: 14 Dec 92 01:56:36 GMT
- Sender: <li@sce.carleton.ca>
- Organization: Indiana University
- Lines: 45
- X-Mailer: ELM [version 2.3 PL11]
-
-
- Answer to "Math Prblem"
-
- Few days ago, I posted the following msg in Usenet bulletins: sci.math,
- soc.culture.china.
-
- > Math Problem
- > ------------
- >There is a polynomial:
- > -a*y**n + y**(n-1) + y**(n-2) + ... + y + 1 = 0
- >where real number a>0 and the notation "y**n" represents the nth power of y.
- >It's conjectured that this polynomial has a unique positive real solution y.
- >Can you prove it or find a counter example?
-
- Since then, I received many answers. Here I list one due to
-
- >prince@ruccs.rutgers.edu (Alan Prince) Fri, 11 Dec 92 16:17:15 EST
- >
- >Let P(y) be the polynomial in question.
- > First, notice that, since there is one sign-change in
- >the coefficients, P(y) has AT MOST one positive zero, by the
- >Harriot-Descartes rule of signs.
- > Second, notice that P(0) = 1 and P(y) -> -infty as y ->
- >+infty, so that P(y) must become negative for some y>0. Therefore
- >there is AT LEAST one positive zero.
- > QED.
-
- Other people's wits are also acknowledged. They are
-
- Victor Adamchik <victor@wri.com>
- W. Huang <uphhswh%msu.dnet@terra.oscs.montana.edu>
- Shidong Tong <stong@irus.rri.uwo.ca>
- Bob Silverman <bs@linus.mitre.org>
- ZHIGANG XI <XI@BINAH.CC.BRANDEIS.EDU>
- Michael Somos <somos@alpha.ces.cwru.edu>
- xyl00@pteng.amdahl.com (Xiaoyang Luo)
- cheekai@ncb.gov.sg (Chin Chee-Kai)
- <erick@sfu.ca>
-
- I put answers from all of them in a file. If anyone is interested, please
- send me a msg.
-
- Thanks for all
-
- Li Yao
-