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- Path: sparky!uunet!spool.mu.edu!sol.ctr.columbia.edu!destroyer!cs.ubc.ca!unixg.ubc.ca!kakwa.ucs.ualberta.ca!ee.ualberta.ca!gilchr
- From: gilchr@ee.ualberta.ca (Andrew Gilchrist)
- Subject: Power lead inductance
- Message-ID: <gilchr.722515511@ee.ualberta.ca>
- Sender: news@kakwa.ucs.ualberta.ca
- Nntp-Posting-Host: eigen.ee.ualberta.ca
- Organization: University Of Alberta, Edmonton Canada
- Date: Mon, 23 Nov 1992 10:45:11 GMT
- Lines: 24
-
-
- There's no simple way to predict the inductance of your +12 power
- circuit. It depends on not only the size of the wire, but on the
- circuit path. If the +12V wire is physically very close to the
- return circuit (usually chassis), then inductance will be comparatively
- small.
-
- It has to do with the amount of energy stored in the magnetic field.
-
- The self-impedance of a conductor depends on the number of flux-linkages
- inside the conductor. Thus, this is higher for larger wire guage sizes.
- (Hollow conductors have minimal self-inductance... but I still don't see anyone
- running copper plumbing tube in their cars for power).
- SO, it would seem that one should use the smallest wire guage they can get
- away with.
-
- Also note that if the return path is the chassis, the conductor is STEEL.
- The significance of this is that steel is ferromagnetic. This implies
- that the self-impedance will be much higher than for copper.
-
-
- If I find my Westinghouse Power bible, I'll look up the numbers.
-
- Andrew
-