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- From: carabalo@fine.Princeton.EDU (David G. Caraballo)
- Newsgroups: sci.math
- Subject: Choice and Measurability: Con(ZF+M+CC) is true
- Message-ID: <1992Jul24.161921.9655@Princeton.EDU>
- Date: 24 Jul 92 16:19:21 GMT
- Sender: news@Princeton.EDU (USENET News System)
- Organization: Princeton University Mathematics Department
- Lines: 65
- Nntp-Posting-Host: math.princeton.edu
-
- I have made the claim (based on some course notes, later supported by
- a quote from a textbook) that "M is consistent with ZF+CC" is true,
- where M = "all subsets of R^n are Lebesgue measurable"
- CC = Countable Choice
-
- I have received numerous emphatic objections on sci.math regarding
- my claim, yet I will make it once again, with renewed support. One
- major criticism is that I omitted mentioning anything about the existence
- of inaccessible cardinals in making the claim. I asked Ed Nelson about
- the question, and he referred me to Robert Solovay. The following is
- quoted from some of Bob Solovay's letters during our email discussions
- over the past few days. (It is quoted with his permission. For whatever
- it's worth, I found him to be extremely nice as well as helpful.) I am
- quoting a relatively small portion of what he wrote, but I am using his
- words to honor his request that I quote sufficient context that his
- meaning be clear. Any typos are my own or are the fault of the posting
- software.
-
- The claim above is not as strong (or useful) as the result concerning
- DC (the axiom of dependent choices), but it is nevertheless true,
- which is what I have repeatedly claimed. Earlier, I had claimed that
- ZF+M is consistent (as long as ZFC is consistent). This claim is true
- as well, without the need to mention inaccessibles.
-
- David G. Caraballo
- Department of Mathematics, Princeton University
- Fine Hall Room 1106
- ----------------------------------------------------------------------------
-
- From Robert Solovay:
-
- " 1) The statement "ZF + M +CC is consistent" is a statement of
- number theory (which is true). Its truth has nothing to do with the
- existence of inaccessibles in the following precise sense. There are
- models of ZFC
- (a) where the statement is true but there are no inaccessibles;
-
- (b) where the statement is false but there is an inaccessible
- cardinal.
-
- 2) Next we have the question: in which theories can we prove
- this true statement.
-
- In ZFC we can prove:
-
- "ZFC +'there is an inaccessible cardinal' " is consistent if
- and only if "ZF + M + CC" is consistent.
-
- (In fact we can prove this assertion in Peano Arithmetic.)
-
- To reiterate:
-
- 1) Con(ZF+M+CC) is not provable in ZFC
-
- 2) Con(ZF+M+CC) is provable in ZFC + Con (ZFC+I), hence in ZFC
- + two inaccessible cardinals exist.
-
- 3) For us dyed-in-the-wool platonists (I'm a card-carrying member of
- the club), 2) is more than enough grounds to conclude:
-
- Con(ZF +M + CC) is true.
-
- As ever,
-
- Bob Solovay "
-