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- Path: sparky!uunet!usc!zaphod.mps.ohio-state.edu!malgudi.oar.net!ucbeh.san.uc.edu!schoudhu
- From: schoudhu@ucbeh.san.uc.edu
- Newsgroups: sci.math
- Subject: a simple question..
- Message-ID: <1992Jul22.103242.1545@ucbeh.san.uc.edu>
- Date: 22 Jul 92 10:32:42 EST
- Distribution: world
- Organization: Univ. of Cincinnati
- Lines: 23
-
-
- Foll. is an easy question that I have no patience to solve and which is needed
- for some work I am doing. Please *mail* me your responses in order to save
- bandwidth:
-
-
- Given expressions for c1(n), c2(n), c3(n), {for n >=5} :
-
- c1(n) = c1(n-1) + c1(n-2) + c1(n-3);
- c2(n) = c2(n-1) + c2(n-2) + c2(n-3);
- c3(n) = c3(n-1) + c3(n-2) + c3(n-3);
-
-
- with the initial conditions:
-
- c1(2) = c2(3) = c3(4) = 1;
- c2(2)=c3(2)=c1(3)=c3(3)=c1(4)=c2(4)=0;
-
- what will be the non-recursive expressions for c1(n), c2(n) and c3(n), in terms
- of n {for all n >= 2} ?
-
- --Spandan Choudury (Computer Science Dept.)
-
-