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- Xref: sparky sci.physics:18551 sci.math:14674
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- From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
- Subject: Re: What's a manifold?
- Message-ID: <1992Nov10.015120.21963@CSD-NewsHost.Stanford.EDU>
- Sender: news@CSD-NewsHost.Stanford.EDU
- Organization: Computer Science Department, Stanford University.
- References: <1992Nov6.024142.6758@galois.mit.edu> <1992Nov6.190913.18507@nas.nasa.gov> <1992Nov10.000228.14551@samba.oit.unc.edu>
- Date: Tue, 10 Nov 1992 01:51:20 GMT
- Lines: 18
-
- In article <1992Nov10.000228.14551@samba.oit.unc.edu> Bruce.Scott@launchpad.unc.edu (Bruce Scott) writes:
- >What about the one-dimensional helix embedded in R^3. Is the helix not a
- >1-manifold? Note that if you compact it along its axis you get a circle
- >(also a 1-manifold--is this S^1?) embedded in R^2. But a circle is a
- >degenerate case of a helix ("stretching" along the axis having vanished)
- >and is not in general a helix.
-
- That projecting the helix along its axis yields another manifold (S1)
- is something of a coincidence. If you tilt the projection slightly you
- no longer get a manifold, since where the coils intersect is not
- homeomorphic to R1. If you keep tilting until the intersections (and
- the cusps) disappear, you get a 1-manifold again, this one
- diffeomorphic to the helix itself (and to R1), but now embedded in the
- plane.
-
- Up to diffeomorphism the helix in R3 *is* R1.
- --
- Vaughan Pratt
-