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- From: tycchow@riesz.mit.edu (Timothy Y. Chow)
- Subject: Re: What's a manifold?
- Message-ID: <1992Nov5.174751.2086@galois.mit.edu>
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- Organization: None. This saves me from writing a disclaimer.
- References: <1992Nov5.004804.24757@galois.mit.edu> <1992Nov5.035214.25991@galois.mit.edu> <1992Nov5.060400.14203@CSD-NewsHost.Stanford.EDU>
- Date: Thu, 5 Nov 92 17:47:51 GMT
- Lines: 40
-
- In article <1992Nov5.060400.14203@CSD-NewsHost.Stanford.EDU> pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt) writes:
- >Ah, now this is starting to sound very interesting and helpful. What I
- >don't understand here is how "living in R^n" is of itself creating
- >complexity and obscurity. I can see that the arbitrariness of f might
- >get in the way. But where does the complexity and obscurity creep in
- >if for example we define a manifold to be a smooth retract of an open
- >subset of R^n? (This is essentially taking the existence of tubular
- >neighborhoods as definitive of manifolds, and is how Bill Lawvere likes
- >to think of them.)
-
- Well, for a start there are some definitions of manifolds that allow
- things that don't embed in R^n. But even if we exclude these cases from
- consideration, there is still good reason not to define manifolds as
- subsets of R^n. The point is that there are many different subsets of
- R^n that represent the "same" manifold. So we really should talk about
- equivalence classes of subsets of R^n, under some suitable equivalence
- relation. Actually it is worse than that since we might want to identify
- certain subsets of R^3 with certain subsets of R^4. This is why I think
- it's cleaner to lay down the axioms for a topological space and use that
- as the basis for the definition of a manifold, rather than have to bring
- in this huge equivalence class of subsets every time you want to talk
- about a manifold.
-
- In fact, I think that despite appearances your retract definition of
- manifold actually contains topological axioms implicitly. Don't you
- really want to say that a manifold is something *homeomorphic* to a
- smooth retract of an open subset of R^n? Once you do this you've already
- taken the implicit step of embracing the axiomatic approach to topology.
-
- None of this is to say that it isn't often convenient to take a subset
- of R^n to *represent* a manifold. Your point is well taken---we don't
- necessarily want to avoid R^n altogether once after we've abstracted
- away from it. But I still think it's simpler to *define* a manifold
- axiomatically rather than make the definition essentially dependent on
- subsets of R^n.
- --
- Tim Chow tycchow@math.mit.edu
- Where a calculator on the ENIAC is equipped with 18,000 vacuum tubes and weighs
- 30 tons, computers in the future may have only 1,000 vacuum tubes and weigh
- only 1 1/2 tons. ---Popular Mechanics, March 1949
-