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- From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
- Newsgroups: sci.physics,sci.math
- Subject: Re: What's a manifold?
- Message-ID: <1992Nov5.060400.14203@CSD-NewsHost.Stanford.EDU>
- Date: 5 Nov 92 06:04:00 GMT
- References: <1992Nov3.204551.29715@lmpsbbs.comm.mot.com> <1992Nov5.004804.24757@galois.mit.edu> <1992Nov5.035214.25991@galois.mit.edu>
- Sender: news@CSD-NewsHost.Stanford.EDU
- Organization: Computer Science Department, Stanford University.
- Lines: 31
-
- In article <1992Nov5.035214.25991@galois.mit.edu> tycchow@riesz.mit.edu (Timothy Y. Chow) writes:
- >
- >Well, this definition has the advantage of being easily motivated and
- >concrete, but as people started studying manifolds more deeply they
- >found that it was often a nuisance to have to be tied to a particular
- >function f to define their manifolds. There were certain geometric
- >properties of manifolds that were "intrinsic" to the surface and didn't
- >really depend on the function f in any essential way. It seemed that
- >what was needed was a way of defining manifolds without having to pick
- >a space R^n for the manifold to live in and specify an explicit function.
- >
- >Hence the modern approach to manifolds is to define them as objects in
- >their own right, without reference to a space that they're imbedded
- >in. This is what motivates the definition that John Baez gives.
- >Notice that he doesn't require the manifold to live in some R^n. The
- >extra abstraction is a small price to pay for the simplification and
- >logical clarity that it yields, as you will appreciate if you study the
- >subject more deeply. Similarly, smooth manifolds and algebraic
- >varieties (and later schemes) are nowadays defined without making them
- >live in R^n.
-
- Ah, now this is starting to sound very interesting and helpful. What I
- don't understand here is how "living in R^n" is of itself creating
- complexity and obscurity. I can see that the arbitrariness of f might
- get in the way. But where does the complexity and obscurity creep in
- if for example we define a manifold to be a smooth retract of an open
- subset of R^n? (This is essentially taking the existence of tubular
- neighborhoods as definitive of manifolds, and is how Bill Lawvere likes
- to think of them.)
- --
- Vaughan Pratt There's no truth in logic, son.
-