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- From: schramm@wisdom.weizmann.ac.il (Schramm Oded)
- Subject: Re: A Conjecture About Packings of Balls
- References: <9211082352.AA24164@zaphod.uchicago.edu>
- Message-ID: <9211130959.AA18671@wisdom.weizmann.ac.il>
- Originator: dan@symcom.math.uiuc.edu
- Summary: The average number of contacts is <= 8 + 4*3^(1/2)
- Sender: Daniel Grayson <dan@math.uiuc.edu>
- X-Submissions-To: sci-math-research@uiuc.edu
- Organization: Weizmann Institute of Science
- X-Administrivia-To: sci-math-research-request@uiuc.edu
- Approved: Daniel Grayson <dan@math.uiuc.edu>
- Date: Fri, 13 Nov 1992 09:59:41 GMT
- Lines: 28
-
- In article <9211082352.AA24164@zaphod.uchicago.edu> greg@math.uchicago.edu (Greg Kuperberg) writes:
- >In article <9211060833.AA05802@wisdom.weizmann.ac.il> you write:
- >>For a finite ball packing P in R^3 [with balls round but not
- >>necessarily congruent], let
- >>a(P)=2(number of tangencies)/(number of balls)
- >...
- >>Conjecture: A = sup a(P) = 12.
- >...
- >>I think I can improve the naive argument above to get something
- >>better than A<=24, but I don't expect to reach A=12.
- >
- >Your expectation is true and your conjecture is false. :-)
- ...
- >which yields a better kind of grout. If you do this once you get a
- >packing with average kissing number 7152/581 > 12.309, and if you
- >iterate, the supremum is (I think) 3486/283 > 12.318.
- ...
-
- Thanks G. Kuperberg. Without much sweat I can show that
- A <= 8 + 4 Sqrt[3] = 14.9282... Unless there is some miraculously
- ingenious idea, I expect that better and better estimates will
- become very difficult. Anyway, the actual value of A is not as
- interesting as the near-optimal packings. Do you think, G. K., that
- your construction gives the true A?
-
- Oded Schramm schramm@wisdom.weizmann.ac.il
-
-
-