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- From: wjcastre@magnus.acs.ohio-state.edu (W.Jose Castrellon G.)
- Newsgroups: sci.math.research
- Subject: Re: combinatorial set theory
- Message-ID: <1992Nov12.220752.28346@magnus.acs.ohio-state.edu>
- Date: 12 Nov 92 22:07:52 GMT
- Article-I.D.: magnus.1992Nov12.220752.28346
- References: <1992Nov11.164014.14768@tolten.puc.cl>
- Sender: Daniel Grayson <dan@math.uiuc.edu>
- Organization: The Ohio State University,Math.Dept.(studnt)
- Lines: 33
- Approved: Daniel Grayson <dan@math.uiuc.edu>
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-
- In article <1992Nov11.164014.14768@tolten.puc.cl> cgutierr@mat.puc.cl (Claudio Gutierrez) writes:
-
- >
- >I need the following result (that can be of comon sense)
- >
- >Exists a family of sets *A* = { Ai}_{i \in \omega}
- >such that there is a family
- >*F* of infinite subsets of *A* with |*F*|=2^{\omega}
- >with the properties:
- > i) Each B \in *F* has F.I.P. (The intersection of a
- > finite numbers of elements of each B \in *F* is non empty.
- > ii) For all B \in *F* , the intersection of all the
- > elements of B is empty.
- >iii) For all B={B1,B2,...} \in *F*, B'={B'12,B'2,...} \in *F*
- > there exists n \in |N such that
- > Intersection{B1,...,Bn} and Intersection{B'1,..,B'n}
- > are dosjoint.
- >
-
- Yes, there is such a family: Let A_(i,n) be the set of numbers = i (mod 2^n),
- and call A the (countable) set of all such A_(i,n) 's . Now to get the
- uncountable family B , take all the subsets of A that are totally ordered
- by inclusion (one can take just the ones that are maximal chains, to make it
- easier to visualize). To see that there are 2^Aleph_0 of them, and that
- i, ii and iii hold, note that N is the disjoint union of two elements of A
- (even and odd numbers), and each of these is again the disjoint union of two
- elements of A ... so one can go along 2^Aleph_0 many paths and choose one
- of the two possible sets to get the elements of B : ordered by inclusion,
- finite intersection non-empty, total intersection empty and two different
- elements of B will start to have pairwise disjoint elements from the moment
- their paths differ, forcing iii to hold.
-
- I wonder what application you have in mind for this, is it a forcing argument?
-