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- Xref: sparky sci.math:14779 sci.physics:18704
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- From: ask@ucscb.UCSC.EDU (Andrew Stanford Klingler)
- Newsgroups: sci.math,sci.physics
- Subject: Re: Three-sided coin
- Date: 11 Nov 1992 21:17:48 GMT
- Organization: University of California; Santa Cruz
- Lines: 29
- Sender: ask@ucscb.ucsc.edu
- Message-ID: <1drt9sINN7hu@darkstar.UCSC.EDU>
- References: <1992Nov10.032643.10467@galois.mit.edu> <1dp0m9INNkq6@agate.berkeley.edu> <1992Nov11.061630.22658@galois.mit.edu>
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- In article <1992Nov11.061630.22658@galois.mit.edu> jbaez@riesz.mit.edu (John C. Baez) writes:
- >limits). The dynamics counts.
- >
- >>Note that this would make the surface area of the edge \sqrt{2} times the
- >>surface area of each face, contradicting my original guess that the area
- >>determined the likelihood... I stick with the solid angle approach, though.
- >
- >Solid angle seems right in the limit of a tossed coin that
- >achieves a random orientation and then floats down through honey, i.e.
- >gently, so that it's bound to land on the side that is "pointing down".
- >But clearly this is not how an actual tossed coin works.
- >
- >I think this is a job for experimentalists.
- >
- >
- Actually, I don't even think this is riight in the theoretical limit.
- Coins "flip nicely" because they're nearly two-dimensional symmetric objects.
- If I remember my mechanics correctly, the only stable rotations are about the
- inertial axes with the highest and lowest moments. In this case that means
- the "vertical" axis and any "horizontal" axis. I don't recall how to
- compute the angular trajectory of an object with an arbitrary initial
- orientation and spin, but the general answer will not be proportional times
- for proportional solid angles. If the coin is "nicely flipped" it should
- be proportional times for proportional pure angles, giving a "floating
- through honey" solution h=d. But as you say, this is far from relevant
- to a real throw.
-
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-