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- Path: sparky!uunet!destroyer!cs.ubc.ca!unixg.ubc.ca!unixg.ubc.ca!israel
- From: israel@unixg.ubc.ca (Robert B. Israel)
- Newsgroups: sci.math
- Subject: Re: Mercator Projection
- Date: 10 Nov 92 18:51:18 GMT
- Organization: The University of British Columbia
- Lines: 35
- Message-ID: <israel.721421478@unixg.ubc.ca>
- References: <israel.721212129@unixg.ubc.ca> <1992Nov8.214329.27209@CSD-NewsHost.Stanford.EDU> <israel.721352141@unixg.ubc.ca> <1992Nov10.020408.22139@CSD-NewsHost.Stanford.EDU>
- NNTP-Posting-Host: unixg.ubc.ca
-
- In <1992Nov10.020408.22139@CSD-NewsHost.Stanford.EDU> pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt) writes:
-
- >In article <israel.721352141@unixg.ubc.ca> israel@unixg.ubc.ca (Robert B. Israel) writes:
- >>If you conformally map the sphere with the North and South poles removed,
- >>1-1 onto a cylinder, don't you have the Mercator projection up to
- >>translation and reflection?
-
- >This would imply that the only conformations (is that the word?) of the
- >cylinder onto itself are translations and reflections. Is that true?
-
- Yes. The easiest way to see this is to go back to the sphere with poles
- removed. Let f be a conformal mapping of this 1-1 onto itself. I assume
- that f is orientation preserving (this may or may not be part of your
- definition of "conformal" - if not, a reflection will fix it). At the
- poles (in the geographical sense), f can't have an essential singularity
- because it's 1-1. So f is a meromorphic function, i.e. extends to a
- mapping of the whole sphere to itself. This will either leave the poles
- fixed or interchange them - if it interchanges them, apply a reflection
- through the centre of the sphere (corresponding to 180 degree rotation of
- the cylinder). Now map the sphere with North pole removed to the complex
- plane by stereographic projection, the South pole mapping to 0. Then
- f corresponds to an entire function with a pole (in the analytic sense)
- at infinity, i.e. a polynomial. Since it maps 0 to itself and is 1-1,
- the only possibilities are f(z) = c z for constant, nonzero c. This is
- a two-dimensional, connected group of mappings, so it must correspond to
- the translations on the cylinder (also a two-dimensional group of
- conformal mappings).
-
- >--
- >Vaughan Pratt
- --
- Robert Israel israel@math.ubc.ca
- Department of Mathematics or israel@unixg.ubc.ca
- University of British Columbia
- Vancouver, BC, Canada V6T 1Y4
-