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- Path: sparky!uunet!utcsri!torn!utzoo!dciem!jorchard
- From: jorchard@dciem.dciem.dnd.ca (Jeff Orchard)
- Newsgroups: sci.math
- Subject: Re: Simple Diff Eq
- Message-ID: <6600@dciem.dciem.dnd.ca>
- Date: 10 Nov 92 14:02:04 GMT
- Distribution: na
- Organization: Defence and Civil Institute of Environmental Medicine
- Lines: 29
-
- Newsgroups: sci.math
- Subject: Re: Simple Diff Eq
- Summary:
- Reply-To: jorchard@dretor.dciem.dnd.ca
- Distribution: na
- Organization: Defence and Civil Institute of Environmental Medicine
- Keywords:
-
- >(Jonathan Katz) writes:
- >>(Ric Peregrino) writes:
- >>|> df(x)/dx - 1/f(x) = 0
- >>
- >>I don't know what kind of information you're looking for, but the
- >answer is
- >>f(x)=(2x)^.5
- >
- > Careful there! That should be f(x) = sqrt(2x + c) where c is
- > chosen to satisfy the initial or boundary conditions.
- >
- > Marc R. Roussel
-
- Careful again... the actual answer is
-
- f(x) = +- sqrt(2x+c) (Positive OR Negative)
-
- (Picky, picky!!!) :-)
-
- Jeff Orchard jorchard@dretor.dciem.dnd.ca
- Dept. of National Defence, Toronto, Canada
-