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- Newsgroups: sci.math
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- From: wjcastre@magnus.acs.ohio-state.edu (W.Jose Castrellon G.)
- Subject: Re: Assorted questions and problems
- Message-ID: <1992Nov9.224436.10471@magnus.acs.ohio-state.edu>
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- Organization: The Ohio State University,Math.Dept.(studnt)
- References: <1992Nov8.181631.13298@Princeton.EDU> <96778@netnews.upenn.edu> <1992Nov9.191022.12493@Princeton.EDU>
- Date: Mon, 9 Nov 1992 22:44:36 GMT
- Lines: 37
-
- In article <1992Nov9.191022.12493@Princeton.EDU> tao@potato.princeton.edu (Terry Tao) writes:
-
- >|> >(3) Assume the axiom of choice and the axiom of the continuum. Is it
- >|> >true that two chains (totally ordered sets) which both have the
- >|> >cardinality of the continuum have a one-to-one and onto order
- >|> >preserving mapping betweem them?
- >|>
- >
- >OK, so I screwed up this question. I have a dozen different counterexamples
- >now of the original question. I'll rephrase this question into two different
- >ones
- >
- >(3a) if you assume that the chains are unbounded above and below, and are
- >dense, i.e. between any two elements there is a third, is the above now true?
- >
-
- There is still a counterexample: (0,1) and (0,1) together with a set
- order isomorphic to the rationals, all of whose elements you'll call bigger
- than the ones of (0,1). However if you assume that both sets are _superdense_
- (I dont know the standard term): i.e. for every pair A, B of countable subsets
- if every element of A is strictly smaller than every element of B, then there
- is a x in between; then in this case by a back-and-forth argument (same as
- for showing that all dense unbounded countable orderings are isomorphic to Q)
- it turns out to be true.
-
- >(3b) is (3) true if you remove the "onto" criterion, i.e. is there an order
- >imbedding from the first chain to the other?
- >
-
- Still there is a counterexample: One cannot map the first uncountable ordinal
- in an order preserving fashion into the real numbers, one can even get a pair
- of dense sets with no order preserving map of anyone into the other [same
- technique].
-
- >Thank you for the large number of responses.
- >
- >Terry
-