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- Path: sparky!uunet!mozz.unh.edu!kepler.unh.edu!dvf
- From: dvf@kepler.unh.edu (David V Feldman)
- Newsgroups: sci.math
- Subject: Re: Univariate polynomial equations and the FAQ
- Date: 9 Nov 1992 05:12:34 GMT
- Organization: University of New Hampshire - Durham, NH
- Lines: 34
- Message-ID: <1dks02INNo3b@mozz.unh.edu>
- References: <1992Nov3.185747.2911@sun0.urz.uni-heidelberg.de> <1d72mnINNq2p@mozz.unh.edu> <1992Nov6.184527.20793@sun0.urz.uni-heidelberg.de>
- NNTP-Posting-Host: kepler.unh.edu
-
- In article <1992Nov6.184527.20793@sun0.urz.uni-heidelberg.de> gsmith@clio.uucp (Eugen W. Schmidt) writes:
- >In article <1d72mnINNq2p@mozz.unh.edu> dvf@kepler.unh.edu (David V Feldman) writes:
- >
- >>Fix an integer m. Let K be the extension of Q obtained by adjoining
- >>all roots of all polynomials of the form
- >> n m
- >> x + a x + ... a
- >> m 0
- >
- >>where the coefficients are rational.
- >
- >This sounds like the algebraic closure of Q, Q-bar.
-
- While it is true that I did not ask the question that I intended to,
- I don't see any reason that K = Q-bar. Remember that m is fixed.
- So I was adjoining roots of polynomials that, for large n , would
- have very few non-zero coefficients. Actually the field K that
- I intend is even larger. Specifically, what I should have said is:
-
- Fix an integer m . Let K be the smallest extension of Q closed under
- the adjunction of all roots of all polynomials of the form
-
- n m
- x + a x + ... a
- m 0
-
- with the a_i in K . Then let s(m) be the smallest degree of a polynomial
- with coefficients in Q and no root in K. Then if m=0, s(0)=5 by
- Galois theory. Again, the question is, what is known about s(m), m>0?
-
- > Eugen W. Schmidt/Der Brahms Gang/IWR/Ruprecht-Karls University
- > gsmith@kalliope.iwr.uni-heidelberg.de
-
- David Feldman
-