home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.math
- Path: sparky!uunet!utcsri!helios.physics.utoronto.ca!alchemy.chem.utoronto.ca!mroussel
- From: mroussel@alchemy.chem.utoronto.ca (Marc Roussel)
- Subject: Re: Simple Diff Eq
- Message-ID: <1992Nov9.154558.6261@alchemy.chem.utoronto.ca>
- Organization: Department of Chemistry, University of Toronto
- References: <13390031@hpspdla.spd.HP.COM> <1992Nov8.191725.14856@athena.mit.edu>
- Date: Mon, 9 Nov 1992 15:45:58 GMT
- Lines: 14
-
- In article <1992Nov8.191725.14856@athena.mit.edu> frisch1@athena.mit.edu
- (Jonathan Katz) writes:
- >In article <13390031@hpspdla.spd.HP.COM>, ric@hpspdla.spd.HP.COM
- >(Ric Peregrino) writes:
- >|> df(x)/dx - 1/f(x) = 0
- >
- >I don't know what kind of information you're looking for, but the answer is
- >f(x)=(2x)^.5
-
- Careful there! That should be f(x) = sqrt(2x + c) where c is
- chosen to satisfy the initial or boundary conditions.
-
- Marc R. Roussel
- mroussel@alchemy.chem.utoronto.ca
-