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- From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
- Subject: Re: definition of topological space
- Message-ID: <1992Nov7.044233.28977@CSD-NewsHost.Stanford.EDU>
- Keywords: Topology; Open sets; Continuity
- Sender: news@CSD-NewsHost.Stanford.EDU
- Organization: Computer Science Department, Stanford University.
- References: <1992Nov5.094404.15550@infodev.cam.ac.uk> <1992Nov5.165530.21866@CSD-NewsHost.Stanford.EDU> <1992Nov6.091200.7105@leland.Stanford.EDU>
- Date: Sat, 7 Nov 1992 04:42:33 GMT
- Lines: 132
-
- In article <1992Nov6.091200.7105@leland.Stanford.EDU> ledwards@leland.Stanford.EDU (Laurence James Edwards) writes:
- >In article <1992Nov5.165530.21866@CSD-NewsHost.Stanford.EDU>, pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt) writes:
- >|> In article <1992Nov5.094404.15550@infodev.cam.ac.uk> rgep@emu.pmms.cam.ac.uk (Richard Pinch) writes:
- >|> >Incidentally, {1,2,3} {} {1} is a perfectly good family of open sets
- >|> >for a topology on {1,2,3}: but it has nothing to do with epsilons and
- >|> >deltas.
- >|>
- >|> Well, not nothing at all. Any topology determines the nearness
- >|> relation: point x is NEAR set Y when x does not belong to Y but does
- >|> belong to every closed set containing Y (i.e. to the CLOSURE of Y).
- >|>
- >|> (The points near the INTERIOR of X (= complement of closure of
- >|> complement of X) constitute the FRONTIER of X. The BOUNDARY of X is
- >|> the portion of its frontier lying within X, equivalently those points
- >|> near the complement of X. So the frontier of X is the boundary of X
- >|> plus all points near X.)
- >|>
- >|> Applying this to the example, 1 is a hermit (is near no set) while 2 is
- >|> near {1}, {3}, and {1,3}, and 3 is near {1}, {2}, and {1,2}. (So x
- >|> being near singleton {y} need not imply that y is near singleton {x}.)
- >|>
- >|> This is the topologically abstract expression of the general idea of
- >|> epsilon-delta.
- >
- >Ok, this was one of the things that was confusing me with regard to finite
- >sets. To me it seemed that determining the closure requires the definition
- >of neighborhood and that neighborhood depends on the definition of near,
- >but in the above near depends on the definition of closure. I'm having a
- >hard time figuring out why this isn't a circular chain of definitions.
- >To my untrained eye it would seem that a set in the absence of any
- >ordering or distance relationships cannot be categorized as open or
- >closed.
- >
- >Larry Edwards
-
- No circularity, these are alternative definitions. Let me collect
- three of them here in the one place to make this clearer. A
- topological space is a set X with any one of the following equivalent
- structures:
-
- 1. A set of subsets called open sets.
- 2. A function cl:P(X)->P(X) mapping subsets to subsets, called closure.
- 3. A binary relation near(x,Y) relating a point x to a subset Y.
- (For a 4th, a reflexive version of 3, see Gareth McCaughan's msg today
- on nbhd's.)
-
- There are two things: axioms to go with each structure, and how to get
- the other structures from any given one.
-
- Axioms:
- 1. The open sets include the empty set and X, and are closed under binary
- (hence finite) intersection and arbitrary union.
- 2. cl is monotone, idempotent, and increasing. That is, X<Y -> cl(X)<cl(Y),
- cl(cl(X))=X, X<cl(X) (where "<" denotes "subset of").
- 3. near(x,Y) is irreflexive, monotone in Y, and &-additive in Y. That is,
- not near(x,{x}), Y<Z and near(x,Y) and x not in Z -> near(x,Z), and
- near(x,Y&Z) iff near(x,Y)&near(x,Z) (& is intersection and conjunction).
-
- Getting between these is probably best left as an exercise.
-
- As far as |f(x)-f(y)| is concerned, following Mac Lane there are two
- reasons to be more abstract, simplicity and unity. The simplicity
- reason is that when an argument goes through with a subset of the
- assumptions, it only clutters things up to have the other assumptions
- built into your proof. The unity reason is that that argument is also
- applicable to other models of your minimal assumptions, in which case
- insisting on keeping the redundant assumptions in your proof needlessly
- rules out these other applications. I can think of no better
- definition of mathematics than as the subject of simplicity and unity
- of thought.
-
- The way I think intuitively about arbitrary topologies (i.e. not even
- assuming T0) is to visualize not just the open sets by the themselves
- but always paired with their complementary closed sets. That way you
- can think of each pair (O,C) as one of the ways the space can tear in
- half, with the frontier of the tear generously given to the closed half
- C. The trivial tear (one side empty) is *always* legal.
-
- From this perspective it can be seen that a topological space could
- just as well be defined as the pairs (Y,Z) such that Y is *not* open
- (and hence Z is not closed). That is, give all the ways in which the
- space is "stuck together". (So the discrete topology, all sets open,
- says that the space "crumbles into dust" in the sense that it is not
- held together in any way, while the coarse topology, only 0 and X open,
- says it is titanium and there is no way it can come apart except
- trivially. The usual topology on the real plane says you can tear it
- apart in relatively tame ways, but ripping out the rationals is
- forbidden, the plane is a bit too sticky for that.)
-
- This view has the nice feature that you can define a continuous map
- f:X->Y to be one that preserves stickiness. If (U,V) is one of the
- ways space X cannot fall apart, then Y cannot fall apart with one half
- containing f(U) and the other half containing f(V). This neatly
- captures the idea that continuous maps can't do their own tearing, they
- can only tear where the domain of f already permits it.
-
- The meaning of the T0 axiom is that there are no identical twins.
- Identical twins are two points having the same membership status in
- every open set: both in or both out. T0 does for topological spaces
- what antisymmetry does for partially ordered sets, namely it prevents
- equivalence classes having more than one element. (There is a one-one
- correspondence between finite topologies and finite preorders
- (reflexive transitive binary relations), whence a finite T0 topology is
- exactly a finite partial order. In the infinite case one talks of an
- ordered topological space. The partial order defined by cl is x<=y
- just when cl({x}) subset cl({y}).)
-
- The stronger T1 axiom says that the only good partial order is a
- discrete partial order: the closure of singleton cannot lie inside the
- closure of a different singleton, so x <= y (as defined above) iff
- x=y. (This is equivalent to saying that all singletons are closed.)
- Since 99.9% of topology is done with T1 spaces this is why you don't
- hear about ordered spaces, nontrivial ones don't arise in practice.
- (This is not universally true however: the Stone duality of
- distributive lattices and Stone spaces requires the full generality of
- T0 spaces, and many applications of topology in computer science
- similarly violate T1.)
-
- So finite T1 topologies are discrete (since T0 topologies are partial
- orders and we disallow nontrivial x <= y). The coarsest possible
- infinite T1 topology has for its closed sets exactly the finite sets
- (and of course the whole space). Hence the open sets are the cofinite
- sets (finite complements), and hence no two open sets are disjoint. If
- we think of open sets as neighborhoods this means that any two
- neighborhoods of two distinct points must intersect. But real geometry
- isn't like that, any two points on the plane have disjoint
- neighborhoods, that is, can be housed off from each other, so we call
- this the Hausdorff or T2 property.
-
- Locales are nice too, but I think I'll stop while I'm ahead (if I am).
- --
- Vaughan Pratt There's no truth in logic, son.
-