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- Newsgroups: sci.logic
- Path: sparky!uunet!stanford.edu!CSD-NewsHost.Stanford.EDU!Sunburn.Stanford.EDU!pratt
- From: pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt)
- Subject: Re: Impredicativity - was: Russell's Paradox
- Message-ID: <1992Nov5.174527.22908@CSD-NewsHost.Stanford.EDU>
- Sender: news@CSD-NewsHost.Stanford.EDU
- Organization: Computer Science Department, Stanford University.
- References: <Bx693z.H37@cantua.canterbury.ac.nz> <1992Nov4.073717.22625@CSD-NewsHost.Stanford.EDU> <1992Nov5.164251.29649@guinness.idbsu.edu>
- Date: Thu, 5 Nov 1992 17:45:27 GMT
- Lines: 11
-
- In article <1992Nov5.164251.29649@guinness.idbsu.edu> holmes@garnet.idbsu.edu (Randall Holmes) writes:
- >You do not "weaken" FA to AFA; ZFC- + FA and ZFC- + AFA are both
- >stronger than ZFC-, but neither is stronger than the other.
-
- I guess this must be another of my misconceptions. My general
- impresssion was that AFA was automatically true under FA, by virtue of
- the latter saying that only "unwound" graphs were permitted, and that
- every chain on the unwinding had to terminate. So what's an example FA
- situation contradicting AFA?
- --
- Vaughan Pratt There's no truth in logic, son.
-