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- From: holmes@garnet.idbsu.edu (Randall Holmes)
- Subject: Re: consequences of the Axiom of Choice
- Message-ID: <1992Oct14.181013.3894@guinness.idbsu.edu>
- Keywords: Axiom of choice; Cartesian product
- Sender: usenet@guinness.idbsu.edu (Usenet News mail)
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- Organization: Boise State University
- References: <1992Oct1.152704.16387@CSD-NewsHost.Stanford.EDU> <1af9g6INN6d2@function.mps.ohio-state.edu> <1992Oct9.192054.11140@ariel.ec.usf.edu>
- Date: Wed, 14 Oct 1992 18:10:13 GMT
- Lines: 43
-
- In article <1992Oct9.192054.11140@ariel.ec.usf.edu> mccolm@darwin.math.usf.edu. (Gregory McColm) writes:
- >In article <1af9g6INN6d2@function.mps.ohio-state.edu> edgar@function.mps.ohio-state.edu (Gerald Edgar) writes:
- >>In article <1992Oct1.152704.16387@CSD-NewsHost.Stanford.EDU> pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt) writes:
- >>>Bertrand Russell used to explain choice this way. Imagine you are
- >>>blessed with infinitely many pairs of shoes and socks. You wish to
- >>>choose one of each pair. With the shoes it is easy: you could take
- >>>all the left ones, or all the right ones. But can you choose one sock
- >>>from each pair? To claim that you can is to assert the axiom of
- >>>choice.
- >>
- >>So, let's try to find a good mathematical example to illustrate Russel's
- >>explanation. Explicitly find a countably infinite set S of (unordered) pairs,
- >>for which a choice function is not obvious. [More technical details.
- >>The set S should be explicitly and uniquely specified in the language of ZF.
- >>It should be provable in ZF that it is a countable set of pairs.]
- >>
- >>An UNCOUNTABLE set of pairs with no obvious choice function is
- >>easy: take the set of ALL pairs of sets of real numbers.
- >>--
- >
- >
- >Won't work: given any pair {r,s}, choose the smaller one.
- >In fact, no set with a constructible linear order will work,
- >and an infinite set with no constructible linear ordering
- >will be a strange beast indeed.
- >
- >-----Greg McColm
-
- On the contrary, the set of equivalence classes of real numbers of
- real numbers under tail equivalence of decimal expansions (eventual
- equivalence of some decimal expansion) can fail to have a
- constructible linear ordering, I believe. Of course, under V = L, it
- does, but the order is not natural... The identical consideration
- applies to the set of equivalence classes of sets of natural numbers
- under the relation of having finite symmetric difference (essentially
- the same example). These may be "strange beasts", of course...
-
-
- --
- The opinions expressed | --Sincerely,
- above are not the "official" | M. Randall Holmes
- opinions of any person | Math. Dept., Boise State Univ.
- or institution. | holmes@opal.idbsu.edu
-