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- From: mccolm@darwin.math.usf.edu. (Gregory McColm)
- Newsgroups: sci.math
- Subject: Re: consequences of the Axiom of Choice
- Keywords: Axiom of choice; Cartesian product
- Message-ID: <1992Oct9.192054.11140@ariel.ec.usf.edu>
- Date: 9 Oct 92 19:20:54 GMT
- References: <1992Oct1.084836.14057@infodev.cam.ac.uk> <1992Oct1.152704.16387@CSD-NewsHost.Stanford.EDU> <1af9g6INN6d2@function.mps.ohio-state.edu>
- Sender: news@ariel.ec.usf.edu (News Admin)
- Organization: Univ. of South Florida, Math Department
- Lines: 26
-
- In article <1af9g6INN6d2@function.mps.ohio-state.edu> edgar@function.mps.ohio-state.edu (Gerald Edgar) writes:
- >In article <1992Oct1.152704.16387@CSD-NewsHost.Stanford.EDU> pratt@Sunburn.Stanford.EDU (Vaughan R. Pratt) writes:
- >>Bertrand Russell used to explain choice this way. Imagine you are
- >>blessed with infinitely many pairs of shoes and socks. You wish to
- >>choose one of each pair. With the shoes it is easy: you could take
- >>all the left ones, or all the right ones. But can you choose one sock
- >>from each pair? To claim that you can is to assert the axiom of
- >>choice.
- >
- >So, let's try to find a good mathematical example to illustrate Russel's
- >explanation. Explicitly find a countably infinite set S of (unordered) pairs,
- >for which a choice function is not obvious. [More technical details.
- >The set S should be explicitly and uniquely specified in the language of ZF.
- >It should be provable in ZF that it is a countable set of pairs.]
- >
- >An UNCOUNTABLE set of pairs with no obvious choice function is
- >easy: take the set of ALL pairs of sets of real numbers.
- >--
-
-
- Won't work: given any pair {r,s}, choose the smaller one.
- In fact, no set with a constructible linear order will work,
- and an infinite set with no constructible linear ordering
- will be a strange beast indeed.
-
- -----Greg McColm
-