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Text File  |  1992-09-14  |  903 b   |  22 lines
  1. Newsgroups: sci.physics
  2. Path: sparky!uunet!cis.ohio-state.edu!news.sei.cmu.edu!firth
  3. From: firth@sei.cmu.edu (Robert Firth)
  4. Subject: Re: Probability Question
  5. Message-ID: <1992Sep15.120128.16175@sei.cmu.edu>
  6. Organization: Software Engineering Institute
  7. References: <1992Sep14.190245.7926@CSD-NewsHost.Stanford.EDU> <TORKEL.92Sep14223854@bast.sics.se> <1992Sep14.212528.29098@uwm.edu>
  8. Date: Tue, 15 Sep 1992 12:01:28 GMT
  9. Lines: 11
  10.  
  11. In article <1992Sep14.212528.29098@uwm.edu> gunter@csd4.csd.uwm.edu (David O Gunter) writes:
  12.  
  13. >But since there are 4-quarters, the total prob. is
  14. >
  15. >                                8 dtheta
  16. >                          P =  -----------
  17. >                                  Pi
  18.  
  19. There's the error.  There are four quarters, but the probability that the
  20. particle will be in any given quarter is 1/4.  Multiply in that factor,
  21. and you are back to the correct answer of 2dtheta/pi.
  22.