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- Newsgroups: sci.math
- Subject: Re: A Question
- Message-ID: <a_rubin.716591599@dn66>
- From: a_rubin@dsg4.dse.beckman.com (Arthur Rubin)
- Date: 15 Sep 92 21:13:19 GMT
- References: <191avdINNjs4@matt.ksu.ksu.edu>
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- Lines: 23
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- In <191avdINNjs4@matt.ksu.ksu.edu> bubai@matt.ksu.ksu.edu (P.Chatterjee) writes:
-
- >I've been stumped by this problem and can't seem to figure out a way to tackle it.
-
- >It goes like this:
-
- >Characterize the functions f: X --> Y for which P(X) --> P(Y), F(A)=f(A), is
- >
- >a)injective,
- f is injective
-
- >b)surjective, or
- f is surjective
-
- >c)bijective.
- f is bijective
-
- It seems obvious to me.
- --
- Arthur L. Rubin: a_rubin@dsg4.dse.beckman.com (work) Beckman Instruments/Brea
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