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- Newsgroups: sci.math
- Path: sparky!uunet!newsgate.watson.ibm.com!yktnews!admin!platt
- From: platt@watson.ibm.com (Daniel E. Platt)
- Subject: Re: Lebesgue integral (was: Couple of questions
- Sender: news@watson.ibm.com (NNTP News Poster)
- Message-ID: <1992Sep15.153811.17326@watson.ibm.com>
- Date: Tue, 15 Sep 1992 15:38:11 GMT
- Disclaimer: This posting represents the poster's views, not necessarily those of IBM
- References: <1992Sep10.173619.24343@galois.mit.edu> <12tnxa#.kmc@netcom.com> <1992Sep11.130033.26063@watson.ibm.com> <1992Sep15.020445.26398@unixg.ubc.ca>
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- Organization: IBM T.J. Watson Research Center
- Lines: 29
-
- In article <1992Sep15.020445.26398@unixg.ubc.ca>, ramsay@unixg.ubc.ca (Keith Ramsay) writes:
- |> In article <1992Sep11.130033.26063@watson.ibm.com>
- |> platt@watson.ibm.com (Daniel E. Platt) writes:
- |> [...taking out some layers of quotes...]
- |> |> In other words, how badly would you miss them if you threw out the
- |> |> non-Riemann-square-integrable functions from L^2(R^3)?
- |> ...
- |> |I think you would end up flat on your back. The problem is that many
- |> |(most) of the techniques revolving around Fourier series and
- |> |integrals, completeness of a basis, etc, ultimately involve being able
- |> |to evaluate 'improper' integrals as a limit of an integral of a
- |> |sequence of functions.
- |>
- |> I've heard that much (nearly all, perhaps) of what is done with L^2,
- |> regarded as Lebesgue square-integrable functions, modulo functions
- |> supported on sets of measure zero, is just as nicely done (if not
- |> better) by regarding L^2 as the formal completion (relative to the L^2
- |> norm) of a convenient dense subset (where the Lebesgue measure theory
- |> is not needed). I'm not enough of an analyst to confirm this.
-
- That's true if you are only talking about proving convergences; if you
- want to get more formal about how/why Dirac delta's work/what they mean,
- and how the broad diversity of the limits under the integral work, then
- some comment should be made about the added convergence that Lebesgue
- offers that Reimann doesn't. Most of the time, physics majors play
- with these delta 'functions' and don't even realize they aren't functions
- per se. When something acts pathological, they don't know why.
-
- Dan
-