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- Path: sparky!uunet!mcsun!sunic!dkuug!diku!torbenm
- From: torbenm@diku.dk (Torben AEgidius Mogensen)
- Newsgroups: sci.math
- Subject: Re: That Collatz Flu
- Message-ID: <1992Sep14.151916.3719@odin.diku.dk>
- Date: 14 Sep 92 15:19:16 GMT
- References: <BuF596.64L@news.cso.uiuc.edu>
- Sender: torbenm@freke.diku.dk
- Organization: Department of Computer Science, U of Copenhagen
- Lines: 20
-
- levine@symcom.math.uiuc.edu (Lenore Levine) writes:
-
- >(Collatz function: f(n) = n/2 if n is even
- > = (3n + 1)/2 if n is odd.
-
- >It is conjectured that for every n > 0, there is a k such that f^k(n)
- >(the kth iterate of f) = 1.)
-
- >What I'm wondering is: Has it been shown that there are no n > 2 such
- >that f^k (n) = n?
-
- Obviously not, as this would disprove the conjecture: if f^k(n) = n,
- then either there is no j s.t. f^j(n) = 1, or else n=1 or n=2.
-
- In general, a sequence of integers will either be non-repeating (and
- thus grow arbitrarily large) or else eventually cycle with period p
- (where p may be 1). The only known cycle in Collatz sequences is
- 1->2->1.
-
- Torben Mogensen (torbenm@diku.dk)
-