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- Path: sparky!uunet!stanford.edu!rutgers!ub!acsu.buffalo.edu!kriman
- From: kriman@acsu.buffalo.edu (Alfred M. Kriman)
- Newsgroups: sci.math
- Subject: Re: Chess Problem
- Message-ID: <BuJvx3.34@acsu.buffalo.edu>
- Date: 14 Sep 92 04:17:27 GMT
- References: <1992Sep12.222402.14408@nmt.edu>
- Sender: nntp@acsu.buffalo.edu
- Organization: UB
- Lines: 20
- Nntp-Posting-Host: lictor.acsu.buffalo.edu
-
- In article <1992Sep12.222402.14408@nmt.edu> jmarlan@titan.nmt.edu
- (Jon Marlan) issues a challenge:
- > FOLLOW-UP QUESTION FOR EXTRA CREDIT:
- > Determine the odds for doing the same with eight bishops! ;-)
- >
- >In article <BuGA8t.DL8@cmptrc.lonestar.org> carter@cmptrc.lonestar.org
- (Carter Bennett) writes:
- >I'll give this one a try.
- >
- >Let B(i) = # of available "safe" places for i'th bishop
- >
- >B(1) = 64
- >B(2) = 64-8 = 56
- > .
- > .
- > .
-
- It's not so simple. The number of safe squares depends not only on the
- number of bishops previously placed (safely), but also on their locations.
- B(2) as given is correct only if the first bishop is placed at a corner.
-