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- From: dlb@fanny.wash.inmet.com (David Barton)
- Newsgroups: sci.math
- Subject: Re: Chess Problem
- Message-ID: <DLB.92Sep12142642@fanny.wash.inmet.com>
- Date: 12 Sep 92 19:26:42 GMT
- References: <BuFpLp.9nI@ecf.toronto.edu> <BuGA8t.DL8@cmptrc.lonestar.org>
- <DLB.92Sep12135413@fanny.wash.inmet.com>
- Sender: news@inmet.camb.inmet.com
- Organization: Intermetrics Inc., Washington Division, USA
- Lines: 29
- In-Reply-To: dlb@fanny.wash.inmet.com's message of Sat, 12 Sep 1992 18:54:13 GMT
- Nntp-Posting-Host: fanny.wash
-
- In article <DLB.92Sep12135413@fanny.wash.inmet.com>
- dlb@fanny.wash.inmet.com (David Barton) writes:
-
- Let's see. The first rook can go anywhere; it eliminates fifteen
- squares from possible next placement, leaving 49. The second rook has
- 49 out of 64 squares to choose from and eliminates thirteen squares
- from the next possible placement set, leaving 36. Continuing:
-
- p = 49/64 * 36/64 * 25/64 * 16/64 * 9/64 * 4/64 * 1/64
-
- Oops. I forgot to eliminate the square sat upon by each rook as they
- occupy spaces. Thilly moi.
-
- I used to fail math tests like this.
-
- p = 49/63 * 36/62 * 25/61 * 16/60 * 9/59 * 4/58 * 1/57
-
- Resulting in
-
- p = 9.10946533801e-6
-
- or
-
- p = .00000910946533801
-
- What's a factor of two between friends.
-
- Dave Barton
- dlb@hudson.wash.inmet.com
-