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- From: goodman@bright.uoregon.edu (Albert Goodman)
- Newsgroups: sci.math
- Subject: Tiling sphere by triangles (Re: 3 space terahedron-packing)
- Message-ID: <1992Sep11.182727.28044@nntp.uoregon.edu>
- Date: 11 Sep 92 18:27:27 GMT
- Article-I.D.: nntp.1992Sep11.182727.28044
- References: <f#tng3h.spworley@netcom.com>
- Sender: news@nntp.uoregon.edu
- Organization: Dept. of Mathematics, University of Oregon, Eugene OR 97403-1222
- Lines: 26
-
- In article <f#tng3h.spworley@netcom.com> spworley@netcom.com (Steven) writes:
- >I am trying to implement an interpolation algorthim over 3D space by
- >using a "grid" of tetrahedrons. What I need to compute is a complete
- >tiling of 3-space with unit length tetrahedrons: ie, given an XYZ
- >location, identify the four points of the tetrahedron that encloses
- >that location in this "packed" space. [...]
-
- This reminds me very much of something someone asked me about
- recently, although really I think it's an unrelated question.
-
- Instead of 3-space, consider the surface of a sphere (such as [an
- approximation to] the surface of the earth), and suppose we want to
- find a tiling or "grid" of triangles which divide up the surface of
- the sphere into many small pieces all of the same area (and preferably
- all the same shape, i.e. congruent triangles). (Actually the original
- question didn't have to use triangles, just some constant shape, but
- triangles seems perhaps a nice choice; trying to use squares, as would
- be the obvious solution on a flat surface, doesn't seem to work on the
- sphere to get all of the same area.)
-
- I think I already know a way to do this (suggested by someone I
- mentioned this to privately), but I haven't worked out the details
- yet (in particular an algorithm for finding which triangle contains
- any specified point). So first I'm wondering if anyone has considered
- such a thing before.
- -- Albert Goodman (goodman@math.uoregon.edu)
-