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- Path: sparky!uunet!wupost!spool.mu.edu!agate!wish-bone.berkeley.edu!mazzarel
- From: mazzarel@wish-bone.berkeley.edu (Ariel Mazzarelli)
- Newsgroups: sci.math
- Subject: Re: Couple of questions
- Date: 9 Sep 1992 20:45:38 GMT
- Organization: U.C. Berkeley Math. Department.
- Lines: 16
- Message-ID: <18lnpiINN1qk@agate.berkeley.edu>
- References: <1992Sep9.102457.15049@news.columbia.edu>
- NNTP-Posting-Host: wish-bone.berkeley.edu
-
- In article <1992Sep9.102457.15049@news.columbia.edu> pvl2@cunixb.cc.columbia.edu (Priscilla V Loanzon) writes:
- >Could someone please explain to me a few basic things:
- >
- >What is the logic used to answer questions of the below type?
- >
- >1) If the finite group G contains a subgroup of order 7 but no element
- >(other than the identity) is its own inverse then the order of group G
- >could be (a)27 (b)28 (c)35 (d)37 (e)42.
- >
-
- If a prime p divides the order of a group, then the group must contain
- an element of order p (Cauchy's theorem). Since G has no element of
- order 2, |G| cannot be even, so b & e are eliminated as options. Since
- 7 must divide |G|, a & d are eliminated. That leaves c.
-
- Ariel
-