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- Newsgroups: sci.physics
- Path: sparky!uunet!sun-barr!ames!elroy.jpl.nasa.gov!nntp-server.caltech.edu!stieger
- From: stieger@cco.caltech.edu (Ronald David Stieger)
- Subject: Re: FTL
- Message-ID: <1992Aug28.191225.13143@cco.caltech.edu>
- Sender: news@cco.caltech.edu
- Nntp-Posting-Host: punisher
- Organization: California Institute of Technology, Pasadena
- References: <1830.2A8E1404@catpe.alt.za> <1992Aug18.085010.24910@syma.sussex.ac.uk>
- Date: Fri, 28 Aug 1992 19:12:25 GMT
- Lines: 36
-
- mppu3@syma.sussex.ac.uk (Conor McMenamin) writes:
-
- > Some people don't know when to leave it. I'm one. How's about
- >this. The uncertainty principle states that there is a degree of
- >uncertainty in position and velocity such that the product of the two
- >uncertainties is greater than or equal to something with a h in it and
- >probably some 2 pi's and stuff. (Less chance of being flamed if I keep
- >it vague). If something is going at speeds near c, where is it? Try
- >pointing at it. Therefore delta x is BIG. And delta v is correspondingly
- >small.
- > But the basic result is, if you're dealing with things in terms
- >of the uncertainty principle, you're never going to observe it, so why
- >does it matter?
-
- Remember that the uncertainty principle does NOT say anything about
- uncertainty in velocity. It talks about uncertainty in MOMENTUM.
-
- delta x * delta p_x <= h (or h/2 or hbar, i don't remember)
-
- And momentum, in SR is gamma * m * v, which goes to infinity as v
- approaches c. So a particle travelling at a velocity less than c
- cannot, by uncertainty, be said to maybe be travelling faster than c.
- And a particle with nonzero mass cannot travel at c, and even if it did,
- what difference would it make? Momentum of infinity +/- delta p, hmm...
- sure sounds like it's still infinity to me! Now light's momentum is
- based on it's wavelength, p = h/l, so again uncertainty doesn't affect
- the velocity. In fact, light MUST travel at exactly c, or it doesn't
- exist (i.e. has no energy, E = gamma * m * c^2, if m = 0, gamma = infinity
- ==> v = c), and of course c is implicit in Maxwell's equations.
-
- Well I hope this helped.
-
- --
- --Ron Stieger
- stieger@cco.caltech.edu
- "Everybody wants a rock to wind a piece of string around."-They Might Be Giants
-