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- Path: sparky!uunet!stanford.edu!agate!dog.ee.lbl.gov!csa1.lbl.gov!sichase
- From: sichase@csa1.lbl.gov (SCOTT I CHASE)
- Newsgroups: sci.math
- Subject: Re: Solitaire games
- Date: 4 Sep 92 21:27:06 GMT
- Organization: Lawrence Berkeley Laboratory - Berkeley, CA, USA
- Lines: 29
- Distribution: na
- Message-ID: <26102@dog.ee.lbl.gov>
- References: <Btyo5z.D8q@cs.psu.edu> <1992Sep3.125317.8741@cs.rulimburg.nl> <NICKH.92Sep4105837@VOILA.VENARI.CS.CMU.EDU>
- Reply-To: sichase@csa1.lbl.gov
- NNTP-Posting-Host: 128.3.254.196
- News-Software: VAX/VMS VNEWS 1.3-4
-
- In article <NICKH.92Sep3143716@VOILA.VENARI.CS.CMU.EDU> nickh@CS.CMU.EDU (Nick Haines) writes:
- > I play a game with triplets of digits (such as one finds on 99% of
- > British numberplates),
-
- This reminds me of the "annual puzzle" which appears each January in the
- alumnus section of Technology Review, in a math/games column which appears
- in each issue. (MIT grads get a special insert with class news, MIT
- propaganda, etc.)
-
- Problem: Construct all the numbers from 1 to 100 using all four digits
- of the year (in our case: 1,9,9,2),preferably in order, by interposing
- apropriate operators. For example,
-
- 1 = 1**992
- 2 = 1**99 * 2
- 3 = 1**99 + 2
- 7 = (1**9)*9 - 2
- 16 = 1*(9+9) - 2
-
- and so forth. If you've never tried it before, give it a whack. Warning:
- the best solution does *not* include all 100 numbers in most (if not all) years.
-
- -Scott
- --------------------
- Scott I. Chase "The question seems to be of such a character
- SICHASE@CSA2.LBL.GOV that if I should come to life after my death
- and some mathematician were to tell me that it
- had been definitely settled, I think I would
- immediately drop dead again." - Vandiver
-