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- Path: sparky!uunet!olivea!decwrl!sgi!wdl1!wdl39!mab
- From: mab@wdl39.wdl.loral.com (Mark A Biggar)
- Newsgroups: sci.math
- Subject: Re: p prime, p divides ab => pdivides a or b
- Message-ID: <1992Sep2.204039.29133@wdl.loral.com>
- Date: 2 Sep 92 20:40:39 GMT
- References: <Btyo8q.E63@ux1.cso.uiuc.edu>
- Sender: news@wdl.loral.com
- Organization: Loral Western Development Labs
- Lines: 14
-
- In article <Btyo8q.E63@ux1.cso.uiuc.edu> ceblair@ux1.cso.uiuc.edu (Charles Blair) writes:
- > My recollection is that a number theory course I took presented
- >this as a difficult result, only proved after doing some stuff
- >with the Euclidean algorithm. Is there a proof which avoids that?
-
- Let S be the set of prime factors of ab ignoring powers and Sa and Sb be
- similar sets for a and b respectivly. Now p is an element of S, therefor
- is is an element of Sa union Sb = S, therefore is is a element of
- Sa or Sb by the definition of set union, therefore p|a or p|b QED.
- This all works because of the unique factorization theory.
-
- --
- Mark Biggar
- mab@wdl1.wdl.loral.com
-