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- Newsgroups: sci.math
- Path: sparky!uunet!gatech!mailer.cc.fsu.edu!fsu1.cc.fsu.edu!rose
- From: rose@fsu1.cc.fsu.edu (Kermit Rose)
- Subject: not unique factorization
- Message-ID: <1992Aug27.032241.21816@mailer.cc.fsu.edu>
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- Reply-To: rose@fsu1.cc.fsu.edu
- Organization: Florida State University
- Distribution: world
- Date: 26 AUG 92 23:10:07
- Lines: 36
-
- Hello anyone.
-
- I had read that the integers extended by the sqrt(-5) did not have unique
- factorization into primes. The example was given
-
- 6 = 2 * 3 = (1+sqrt(-5)) * (1 - sqrt(-5))
-
- I considered whether or not this ring could be fixed up by additional
- extension. Perhaps in a larger ring we could have
-
- 6 = a * b * c * d where
-
- a * b = 2
- c * d = 3
- a * c = 1 + sqrt(-5) and
- b * d = 1 - sqrt(-5).
-
- This gives
-
- b = 2/a
-
- c = (1 + sqrt(-5))/a
-
- d = (1 - sqrt(-5))/b = (1 - sqrt(-5)) * (a/2)
-
- One way to have a,b,c,d to be elements of the ring is to define a = 1/2
- to be an element of the ring. Then all powers of 2 becomes units, and the
- factorization 6 = 2 * 3 does not count since 2 is not prime.
-
- Now for my question. Does this fix solve all the cases of non-unique
- factorization in the ring of integers extended by sqrt(-5)?
-
- rose@fsu1.cc.fsu.edu To be sure I see your response, use e-mail.
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