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- Newsgroups: sci.math
- Path: sparky!uunet!usc!wupost!darwin.sura.net!jvnc.net!nuscc!bhonsle!bhonsle
- From: bhonsle@bhonsle.iss.nus.sg (Shailendra K Bhonsle)
- Subject: Re: u(v^n)w prime puzzle - HINTS
- Message-ID: <1992Aug24.024408.14814@nuscc.nus.sg>
- Sender: bhonsle@bhonsle (Shailendra K Bhonsle)
- Organization: Institute of Systems Science, NUS, Singapore
- References: <1992Aug20.043232.5087@nuscc.nus.sg> <1992Aug20.161823.20996@wri.com>
- Date: Mon, 24 Aug 1992 02:44:08 GMT
- Lines: 38
-
- In article <1992Aug20.161823.20996@wri.com>, roach@bikini.wri.com (Kelly Roach) writes:
- |> In article <1992Aug20.043232.5087@nuscc.nus.sg> bhonsle@bhonsle.iss.nus.sg
- |> (Shailendra K Bhonsle) writes:
- |> > |> (2) Let a=|v|=length of v, b=|w|=length of w.
- |> > ...
- |> > As I mentioned in my last article let us take prime p="uw".
- |> > ...
- |> > Now we show that p cannot divide 10^a -1 to complete the proof.
- |> > case 2: b <= a
- |> > SIMPLE, Can you do it ?
- |> > ...
- |>
- |>
- |> Consider:
- |>
- |> u="1",v="36",w="1"
- |> 11, 1361, 136361, 13636361, 1363636361, 136363636361
- |>
- |> Here, a=2, p=11, 10^a-1=99, and p | 10^a-1. So, yes, it
- |> is possible for p to divide 10^a-1. Some more work on this
- |> proof needs to be done before it is complete I think.
- |>
- |> Kelly
- |>
-
-
- I see the mistake. The key is to choose n correctly.
- Let p^i exactly divides 10^a - 1 {where i = 1, 2 ,3 ...}
- then choose n= (p^(i-1))(p-1)
-
- else if p does not divide 10^a-1 then choose n=p-1
-
-
- This will correctly show the required result.
-
-
- Shailendra
- --
-