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- Newsgroups: sci.math.symbolic
- Path: sparky!uunet!news.larc.nasa.gov!lynx.larc.nasa.gov!goodrich
- From: goodrich@lynx.larc.nasa.gov (Mike Goodrich)
- Subject: Re: Can anyone solve this??
- Message-ID: <BtAJKt.89y@news.larc.nasa.gov>
- Sender: news@news.larc.nasa.gov (USENET Network News)
- Organization: NASA Langley Research Center, Hampton, VA USA
- References: <cbc.714097112@milton>
- Date: Thu, 20 Aug 1992 16:38:52 GMT
- Lines: 34
-
- In article <cbc.714097112@milton>, cbc@milton.u.washington.edu (Charles Cook) writes:
- |> As part of my thesis, I came up with this integral that looks as
- |> though it should be easy to solve, however, both Mathematica and
- |> Maple choke on it. I can't seem to find it in *any* integral tables
- |> and I've tried every method I can remember to solve it. Any ideas?
- |>
- |> Here it is:
- |>
- |> /Infinity /X-x0
- |> | | (-y*b) 2 2 1/2
- |> | | e ( x + y ) dx dy
- |> / 0 / -x0
- |>
- |> X and x0 are arbitrary constants as is b. X>x0>0 and b = 1/(X*C) (not
- |> that that should affect things.)
- |> I'm seeking a symbolic closed form solution to this problem (which may
- |> or may not be a pipe dream). Any help or suggestions would be greatly
- |> appreciated.
- |>
- |> Thanks in advance,
- |> Charles Cook
- |> University of Washington
- |>
- |> cbc@u.washington.edu
-
- This looks like a "convert to polar coordinates and integrate over the
- first quadrant" candidate. I.e., change variables from
-
- x,y -> r, theta. (be sure and change limits too)
-
- The tip-off is that r = sqrt( x^2 + y^2 ).
-
-
- ...mike
-