home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.math
- Path: sparky!uunet!wri!news
- From: roach@bikini.wri.com (Kelly Roach)
- Subject: Re: Primes in x_{n+1} = ax_n+b (was Re: u(v^n)w prime puzzle)
- Message-ID: <1992Aug21.184507.4684@wri.com>
- Sender: news@wri.com
- Nntp-Posting-Host: bikini.wri.com
- Organization: Wolfram Research, Inc.
- References: <1992Aug21.103132.29967@ecrc.de>
- Date: Fri, 21 Aug 1992 18:45:07 GMT
- Lines: 37
-
- In article <1992Aug21.103132.29967@ecrc.de> jeanmarc@ecrc.de (Jean-Marc
- Andreoli) writes:
- > Let a,b be integers, and (x_n) be a sequence s.t. x_{n+1} = a x_n + b
- >
- > My question is: does it contain infinitely many primes ?
- >
- > There are trivial cases, where the answer is no:
- > 1/ if (a x_0 + b = x_0) the sequence is constant.
- > 2/ if (a = -1) the sequence alternates between two values x_0 and x_1.
- > 3/ if ((a,b) > 1 or (x_0,b) > 1) then the sequence clearly contains only
- composite numbers.
- >
- > What about the other cases ?
-
-
-
- A different kind of trivial example:
-
- x_0 = 4
- x_{n+1} = 5*x_n + 1
-
- All the x_n are divisible by 2 or 3. Use the Chinese
- Remainder Theorem to get other examples like it. Another
- one:
-
- x_0 = 868
- x_{n+1} = 13*x_n + 1
-
- All the x_n are divisible by 4, 5, 7, or 17. Neither
- of these two examples fit the conditions (1), (2), (3)
- above.
-
- Kelly
-
-
-
-
-