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- Newsgroups: sci.math
- Path: sparky!uunet!munnari.oz.au!bruce.cs.monash.edu.au!dld
- From: dld@cs.monash.edu.au (David L Dowe)
- Subject: int(x*log(x)*((1-x)^n), x=0..1)
- Message-ID: <dld.714296391@bruce.cs.monash.edu.au>
- Summary: int(x*log(x)*((1-x)^n), x=0..1), positive integer n
- Keywords: Hairy integral, Beta function
- Sender: news@bruce.cs.monash.edu.au (USENET News System)
- Organization: Computer Science, Monash University, Australia
- Date: Thu, 20 Aug 1992 07:39:51 GMT
- Lines: 37
-
- Let I(n) = int(x*log(x)*((1-x)^n), x=0..1);
- to use Maple's notation. n is a positive integer. log is ln .
-
- I seek as simple an expression as possible or, that failing, as rapidly
- converging an expression as possible for I(n).
-
- Before you respond (to me rather than the newsgroup, please), let me tell
- you what I do know:
- By parts, int((x^n)*log(x), x=0..1) = -1/((n+1)^2) (1)
-
- Expanding (1-x)^n binomially and using (1) enables us to get a
- fairly simple expression for I(n). But, I would like (if possible) a simpler
- or more rapidly converging expression.
-
- o I also know that, re-writing I(n) as int((1-x)*log(1-x)*(x^n)),x=0..1);
- Taylor expanding log(x) = Sum(i=1,infinity) -(x^i)/i gives
- I(n) = int(-(x^(n+1)) + Sum(i=2,infinity) (x^(n+i))/((i-1)*i) , x=0..1) ;
- and so I(n) = -1/(n+2) + Sum(i=2,infinity) 1/((i-1)*i*(n+i+1)) .
- This also converges more slowly than I would like it to.
-
- o I also "know" that I(n) is rational. I(0) = -1/4, I(1) = -5/36,
- I(2) = -13/144, I(3) = -77/1200, I(4) = -29/600, I(5) = -223/5880,
- I(6) = -481/15680, and Maple Vn4.3 gave me a mammoth expression for
- I(50) in 15 seconds.
- When I gave Maple 4.3 the integral I(n) (n unspecified), it merely
- returned some seconds later with the same initial expression I had given it.
-
- o I also "know" that n*(n-1)*I(n) + log(n + 1/2) converges to
- (I forget whether it's + or - ) +/- 0.42... ,
- the 0.42... possibly (a guess) being something to do with Euler's constant.
-
- I would appreciate (a reference to)
- a proof that I(n) is rational,
- a proof of the convergence result, and the value of "0.42..." , and
- (most importantly) as simple an expression as possible for I(n) .
- __
- Thank you. Yours faithfully, David Dowe.
-