home *** CD-ROM | disk | FTP | other *** search
- Path: sparky!uunet!wupost!usc!rpi!masscomp!usenet.ccur.com!catfish!ocpt!tinton.ccur.com!cjh
- From: cjh@tinton.ccur.com (Christopher J. Henrich)
- Newsgroups: sci.math
- Subject: Re: Binomial like recurrence
- Message-ID: <1992Aug13.230245.13244@tinton.ccur.com>
- Date: 13 Aug 92 23:02:45 GMT
- References: <1992Aug12.100933.13400@aifh.ed.ac.uk> <1992Aug12.171516.24574@menudo.uh.edu>
- Sender: news@tinton.ccur.com (News)
- Organization: Concurrent Computer Corp., Tinton Falls, NJ
- Lines: 41
-
- In article <1992Aug12.171516.24574@menudo.uh.edu> rmverma@cs.uh.edu (Dr. R.M. Verma) writes:
- >In article <1992Aug12.100933.13400@aifh.ed.ac.uk> tw@aisb.ed.ac.uk (Toby Walsh) writes:
- >>
- >>The binomial recurrence,
- >>
- >> c(n,k) = c(n-1,k-1) + c(n-1,k)
- >>
- >>is well known. Has the related recurrence,
- >>
- >> u(n,k) = 2.u(n-1,k-1) + u(n-1,k)
- >>
- >>been studied? Does it have a closed form?
- >>What is its asymptotic behaviour?
- >>
- >>And more generally, how about,
- >>
- >> v(n,k) = a.v(n-1,k-1) + b.v(n-1,k)
- >>
- >>for integer a and b?
- >>
- >>toby
- >
- >Yes, they have been studied and there are answers to some of your
- >questions in the literature.
- >
- >See the paper by Monier in Journal of ALgorithms 1980, and
- >Ch. 8 of The Analysis of Algorithms by Purdom and Brown (more references
- >can be found here).
-
- Dr. Verma's answer sounds like a response to a harder problem than
- the one Mr. Walsh proposed. As far as I can see,
-
- u(n,k) = 2^k . c(n,k).
-
- More generally,
-
- v(n,k) = a^k . b^(n-k) . c(n,k).
-
- Regards,
- Chris Henrich
-