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- Newsgroups: sci.math
- Path: sparky!uunet!snorkelwacker.mit.edu!galois!riesz!tycchow
- From: tycchow@riesz.mit.edu (Timothy Y. Chow)
- Subject: Re: The Converse of Kaplansky's Therorem
- Message-ID: <1992Aug12.222405.3089@galois.mit.edu>
- Sender: news@galois.mit.edu
- Nntp-Posting-Host: riesz
- Organization: None. This saves me from writing a disclaimer.
- References: <1349@newsserver.cs.uwindsor.ca> <1992Aug12.165234.11088@thunder.mcrcim.mcgill.edu>
- Date: Wed, 12 Aug 92 22:24:05 GMT
- Lines: 22
-
- In article <1992Aug12.165234.11088@thunder.mcrcim.mcgill.edu> boshuck@triples.math.mcgill.ca (William Boshuck) writes:
- <In article <1349@newsserver.cs.uwindsor.ca> tarokh@server.uwindsor.ca (TAROKH VAHID ) writes:
- <>Would somebody please tell me if the converse of Kaplansky's Theorem
- <>is true or not? That is if R is a ring with identity such that all the
- <>projective R modules are free, then is R necessarily Local? If we assume
- <>that R does not have identity what could be said?
- <
- <The answer to the first question is NO. Look at the ring of integers.
- <I haven't thought about the second question since I have absolutely
- <no experience with rings without identity.
-
- More generally, consider any principal ideal domain. Any submodule of a
- free module over a principal ideal domain is free. Projective modules are
- direct summands (hence submodules) of free modules. Any non-local PID is a
- counterexample.
-
- I also have no wisdom to offer about rings without unit.
- --
- Tim Chow tycchow@math.mit.edu
- Where a calculator on the ENIAC is equipped with 18,000 vacuum tubes and weighs
- 30 tons, computers in the future may have only 1,000 vacuum tubes and weigh
- only 1 1/2 tons. ---Popular Mechanics, March 1949
-