NetNews Usenet Archive 1992 #18/NN_1992_18.iso/spool/comp/unix/question/10167

Internet Message Format | 1992-08-18 | 1.1 KB

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From: [e-mail]
Newsgroups: comp.unix.questions
Subject: Using find w/ -exec and -ls
Message-ID: <[e-mail]>
Date: 18 Aug 92 20:30:42 EST
Organization: Western Michigan University
Lines: 18

I'm trying to use find with [fe]grep to find all files of a certain extension
that contain a string or regex and then print their names only in a ls -l
format. The problem I am having is that _all_ the files are printed rather
than just the ones that return 0 from grep. This is what I tried:

    % find / -type f -name \*.ext -exec grep -s regex \{\} \; -ls

What am I doing wrong? The only solution I've been able to come up with is to
us xargs to pipe (replace grep -s w/ -l) the output of above minus the -ls
switch to the real ls program. However, in the situation that I want to use this
command line, pipes are not feasable. Also using a pipe to xargs slows this
(already slow) command down.

Anyone?

/Doug
--
Douglas Clifton [[e-mail]]