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- Newsgroups: sci.physics.fusion
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- From: logajan@ns.network.com (John Logajan)
- Subject: Re: Implications of hypothesis of subground states
- Message-ID: <1993Jan25.011105.16977@ns.network.com>
- Sender: news@ns.network.com
- Nntp-Posting-Host: ns
- Organization: Network Systems Corporation
- References: <1993Jan21.192756.23373@ns.network.com> <1993Jan22.203403.1148@asl.dl.nec.com> <1993Jan24.085220.17739@coplex.com>
- Date: Mon, 25 Jan 93 01:11:05 GMT
- Lines: 27
-
- chuck@coplex.com (Chuck Sites) writes:
- >At what point does a hydrino become a neutron?
-
- Never.
-
- A neutron has a rest mass of 939.573 Mev/c^2
-
- A proton has a rest mass of 938.280 Mev/c^2
-
- An electron has a rest mass of 0.511003 Mev/c^2
-
- If a MKF electron/proton pair didn't lose any energy/mass at all to radiation
- then it would come out to be 939.573 - 938.28 - 0.511 = 0.782 Mev's too light
- to be a neutron. But, of course, MKF claim each transistion does radiate,
- thus in a fall from n=ground to n=1/210 (an orbit the size of the proton radius)
- the MKF electron/proton pair lose an additional 0.6 Mev.
-
- Therefore an n=1/210 MKF pair is about 1.4 Mev lighter than a neutron, or about
- 1/6th of one percent lighter than the neutron mass.
-
- The electron/proton pair start out too light in the ground state, and lose mass
- for each subground state, thus at no point will they intersect the mass of the
- neutron.
-
- --
- - John Logajan MS010, Network Systems; 7600 Boone Ave; Brooklyn Park, MN 55428
- - logajan@network.com, 612-424-4888, Fax 612-424-2853
-