home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.image.processing
- Path: sparky!uunet!haven.umd.edu!ames!saimiri.primate.wisc.edu!zaphod.mps.ohio-state.edu!news.acns.nwu.edu!casbah.acns.nwu.edu!lapin
- From: lapin@casbah.acns.nwu.edu (Gregory Lapin)
- Subject: Re: Laplace Edge Detection
- Message-ID: <1993Jan22.162937.13893@news.acns.nwu.edu>
- Followup-To: sci.image.processing
- Keywords: edge
- Sender: Greg Lapin
- Nntp-Posting-Host: unseen1.acns.nwu.edu
- Organization: Northwestern University, Evanston Illinois.
- References: <C0ytox.F7r@watserv1.uwaterloo.ca>
- Date: Fri, 22 Jan 1993 16:29:37 GMT
- Lines: 22
-
- In article <C0ytox.F7r@watserv1.uwaterloo.ca> bgilhuly@hertz.uwaterloo.ca (Barry Gilhuly) writes:
- >
- >
- > | 0 +1 0 |
- > | +1 -4 +1 |
- > | 0 +1 0 |
- >
- >When this matrix is applied to the image, it creates a 'zero-crossing'
- >in the resulting output, giving both positive and negative values at
- >that point. The problem, of course, is the negative values. In a gray-scale
- >image (or even colour I guess), the range isn't supposed to be negative.
- >How is it represented? Or, are the negative values discarded as extraneous
- >since the positive value indicates where the edge is in the image?
- Apply an offset so that a middle gray level (eg 128 in an 8 bit image)
- represents zero. Everything below 128 will be negative and above will be
- positive.
-
- >Thanks for all of your assistance,
- >Barry.
- You're welcome.
- Greg
-
-