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- Newsgroups: sci.math
- Path: sparky!uunet!math.fu-berlin.de!news.th-darmstadt.de!rbg.informatik.th-darmstadt.de!misar
- From: misar@rbg.informatik.th-darmstadt.de (Walter Misar)
- Subject: Re: Fermat's Last Theorem
- Sender: news@news.th-darmstadt.de (The News System)
- Message-ID: <1993Jan6.115438@rbg.informatik.th-darmstadt.de>
- Date: Wed, 6 Jan 1993 10:54:38 GMT
- References: <1993Jan6.092212.9851@bradley.bradley.edu>
- Nntp-Posting-Host: rbhp64.rbg.informatik.th-darmstadt.de
- Organization: TH Darmstadt
- Lines: 47
-
- In article <1993Jan6.092212.9851@bradley.bradley.edu>, pwh@bradley.bradley.edu (Pete Hartman) writes:
-
- [some stuff deleted]
-
- > Hinging on that, it seems apparent that if we go to N = 3, we are
- > dealing with normal 3-D volumes, and it's also apparent that the
- > two lesser volumes would sum to less than the third. For N = 4,
- > we have hypercubes with edges adjacent to the right triangle, and
- > it seems sensible that the two lesser 4-D volumes would be even
- > smaller than the third. Etc. Is there some way to formalize
- > this proof? Is it really a proof?
-
- NO.
- What you are showing is: if a^2+b^2=c^2 holds true then it follows
- that a^3+b^3=c^3 is false (trivial cases like a=b=c=0 excluded).
- Or more generally, that there are values a,b,c for which a^N + b^N = c^N
- isn't true (N>2). But Fermat claimed that there are no integer values
- satisfying the equation.
-
-
- [some more stuff deleted]
-
- > area1^3 + area2^3 + area3^3 = area4^3. Does this really sound
- > feasable to someone who isn't an utter layperson like me? If
- > so, is it "interesting"? Has it been demonstrated already?
- > Does it have any use? Does anyone care?
-
- Also there is no geometrical representation in euclidian space, there
- are examples of this (3^3 + 4^3 + 5^3 = 6^3), and there are methods of
- systematically getting all those values. Related to this, there is
- conjecture of Euler : There aren't any n<N integers, such that the sum
- of this integers each raised to the Nth power is equal to another integer
- raised to the Nth power. But this was proven to be wrong, and an
- example of four 5th powers that some to another 5th power was given.
-
- Anyone know the numbers and who this did ?
-
- > Any comments, criticisms, etc, are welcome. Just my own little
- > shot in the dark....
-
- Before posting a proof of FLT, just check with a local mathematician (or
- however this word is spelled, sorry).
-
- --
- Walter Misar | It is impossible to enjoy
- misar@rbg.informatik.th-darmstadt.de | idling thoroughly unless
- | one has plenty of work to do.
-