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- From: israel@unixg.ubc.ca (Robert B. Israel)
- Newsgroups: sci.math
- Subject: Re: Cantor set problem
- Date: 6 Jan 93 00:18:58 GMT
- Organization: The University of British Columbia
- Lines: 38
- Message-ID: <israel.726279538@unixg.ubc.ca>
- References: <C0EB3o.Kzy@undergrad.math.waterloo.edu>
- NNTP-Posting-Host: unixg.ubc.ca
-
- In <C0EB3o.Kzy@undergrad.math.waterloo.edu> cmspring@undergrad.math.waterloo.edu (Colin Springer) writes:
-
-
- >I'd be interested in any solutions or references anyone might find for the
- >following problem which I've been thinking about recently.
-
- >Problem: Consider the subset of the plane formed by starting with the Cantor
- >set placed on the interval [0,1], and for any two points a, b in this set
- >we construct the circle centered at a passing through b. Does this set have
- >measure zero?
-
- Almost certainly it doesn't. If E is the Cantor set, this set is the
- image of E x E x [0,2pi) under the map (x,y,t) -> x + (y-x)exp(it)
- (considering the plane as the complex numbers). E x E x [0,2pi] has
- Hausdorff dimension greater than 2, so it's likely that the image
- has positive 2-dimensional measure. I don't have a proof, though.
- What I can say is that the interval [-1,2] is contained in your set
- (for t = pi, (2E) - E = [-1,2]).
-
- >If this were the case we could use this set as a "blanket" which could be
- >translated to cover any given circle of radius at most 1, and was of measure
- >zero. Such a "blanket" can be formed to cover rectangles of arbitrary
- >dimensions, but I'm not sure if it's possible. The above construction is my
- >best guess: if it doesn't work, I'd be interested in any other possible
- >construction, with proof if possible.
-
- I.e. (E x [0,1]) union ([0,1] x E) is a set of 2-dimensional measure 0
- containing rectangles of arbitrary dimensions <= 1.
-
- >Have fun with it!
-
- >Colin
-
- --
- Robert Israel israel@math.ubc.ca
- Department of Mathematics or israel@unixg.ubc.ca
- University of British Columbia
- Vancouver, BC, Canada V6T 1Y4
-